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I'm unable to find a way to remove date ordinals while preserving the month in a string.

For example, I would need:

June 12th, 2015

To output to:

June 12, 2015

I've found this post that mentions how to do it, but that form of RegEx does not work with JavaScript.

I'm unable to find a way to remove date ordinals while preserving the month in a string.

For example, I would need:

June 12th, 2015

To output to:

June 12, 2015

I've found this post that mentions how to do it, but that form of RegEx does not work with JavaScript.

  • javascript
  • regex
Share Improve this question edited May 23, 2017 at 10:27 CommunityBot 11 silver badge asked Jan 31, 2016 at 6:10 webdevborninthe90swebdevborninthe90s 391 silver badge3 bronze badges 3
  • Are you using moments library? – Avinash Commented Jan 31, 2016 at 6:11
  • Use .replace(/(\d+)(?:st|nd|rd|th)/, "$1") – Tushar Commented Jan 31, 2016 at 6:11
  • Is the input always just a date, or could it be an entire sentence that happened to contain a date? – user663031 Commented Jan 31, 2016 at 12:31
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3 Answers 3

Reset to default 5

You need to create two capturing group, to select both the number of month (\d+) and its ordinal (st|nd|rd|th). Then replace the string with $1 (first group which is containing the number of month). Something like this:

var str = "June 12th, 2015";
str.replace(/(\d+)(st|nd|rd|th)/, "$1");
//=> June 12, 2015

Live Demo

If you want to use RegEx:

ord_day_pattern = re.pile(r"(?<=\d)(st|nd|rd|th)")
print re.pile(ord_day_pattern).sub("", mystring)

One-liner:

print re.pile(r"(?<=\d)(st|nd|rd|th)").sub("", mystring)

If you don't want to worry about the various ordinals you could use a regex to match any 2 characters preceding a ,. The regex to use would be:

var regex= /[a-z]{2},/;

which matches a string of 2 characters followed by a ,.

For example:

> var regex= /[a-z]{2},/;
> var dateStr = 'June 12th, 2015';
> dateStr.replace(regex, ',');
< 'June 12, 2015'

本文标签： javascriptHow to remove Date Ordinals (st nd RD th)Stack Overflow

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