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How should I do this?

function(id,id2){

    if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
         xmlhttp=new XMLHttpRequest();
    } else { // code for IE6, IE5
         xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
    }

First Request:

   xmlhttp.open("GET", ".php?id="+id, true);

   xmlhttp.send();

Second Request:

   xmlhttp.open("GET", ".php?id2="+id2, true);

   xmlhttp.send();

}

Because in this way doesn't works.

I want to make it in plain javascript, so please do not post answers with jQuery or any library etc.

Thanks

How should I do this?

function(id,id2){

    if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
         xmlhttp=new XMLHttpRequest();
    } else { // code for IE6, IE5
         xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
    }

First Request:

   xmlhttp.open("GET", "http://example./ajax.php?id="+id, true);

   xmlhttp.send();

Second Request:

   xmlhttp.open("GET", "http://example./ajax2.php?id2="+id2, true);

   xmlhttp.send();

}

Because in this way doesn't works.

I want to make it in plain javascript, so please do not post answers with jQuery or any library etc.

Thanks

  • javascript
  • ajax
  • xmlhttprequest
Share Improve this question edited Aug 29, 2010 at 6:48 Adam Halasz asked Aug 29, 2010 at 6:33 Adam HalaszAdam Halasz 58.4k67 gold badges153 silver badges216 bronze badges 2
  • Use JQuery Ajax. it is simple to use. You will find solution for this. – Muneer Commented Aug 29, 2010 at 6:43
  • Thanks for your answer, but I want to make it in plain Javascript :) – Adam Halasz Commented Aug 29, 2010 at 6:46
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2 Answers 2

Reset to default 8

It should work if you create a new xmlhttp object. Currently you are attempting to reuse the same object, which is already performing a query so it will not work.

if you are looking for classic javascript style you can use as the following. But use jQuery as it's simple and prehensive. The one thing to be noted is that the "xmlhr" should be in method (callAjax) scope.

function callAjax(url) {
        var xmlhr;

        if (window.XMLHttpRequest) {
            xmlhr = new XMLHttpRequest();
        } else {
            xmlhr = new ActiveXObject("Microsoft.XMLHTTP");
        }

        xmlhr.onreadystatechange = function () {
            if (xmlhr.readyState == 4 && xmlhr.status == 200) {
                alert(xmlhr.responseText);
            }
        }
        xmlhr.open("GET", url, true);
        xmlhr.send();
    }

    function myFunction(id1, id2) {
        callAjax("http://example./ajax2.php?id2=" + id1);
        callAjax("http://example./ajax2.php?id2=" + id2);
    }

本文标签： javascriptAJAX How to use TWO xmlHttpRequest in parallel in ONE functionStack Overflow

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