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This is my 3rd question about JSON data for jqGrid's subgrid, till now I did not get a single ment. Please somebody help.
my 1st question
and the
2nd one
I am having trouble getting to know the json format to be used by a subgrid in jqGrid. In my 2nd question i asked about the format that I should be using for a particular scenario
for the given image
Is this the proper JSON String?
var myJSONObject = {
"list": [
{
"elementName": "TERM",
"attribute": [
{
"name": "information",
"firstValue": "Required fixes for AIX",
"secondValue": "Required fixes for AIX"
},
{
"name": "name",
"firstValue": "PHCO_34",
"secondValue": "PHCO_34"
},
{
"name": "version",
"firstValue": "1.0",
"secondValue": "2.0"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": false
},
{
"elementName": "Asian-Core.ASX-JPN-MAN",
"attribute": [
{
"name": "information",
"firstValue": "Man",
"secondValue": "Man"
},
{
"name": "name",
"firstValue": "Asian-Core.ASX-JPN-MAN",
"secondValue": "Asian-Core.ASX-JPN-MAN"
},
{
"name": "version",
"firstValue": "B.11.23",
"secondValue": "B.11.23"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": true
}
]
};
If yes, my 1st question this is where i reached so far
$('#pareContent').empty();
$('<div id="pareParentDiv" width="100%">')
.html('<table id="list2" cellspacing="0" cellpadding="0"></table>'+
'<div id="gridpager2"></div></div>')
.appendTo('#pareContent');
var grid = jQuery("#list2");
grid.jqGrid({
datastr : myJSONObject,
datatype: 'jsonstring',
colNames:['Name','Result1', 'Result2'],
colModel:[
{name:'elementName',index:'elementName', width:90},
{name:'isPrasentinXml1',index:'isPrasentinXml1', width:100},
{name:'isPrasentinXml2',index:'isPrasentinXml2', width:100},
],
pager : '#gridpager2',
rowNum:10,
scrollOffset:0,
height: 'auto',
autowidth:true,
viewrecords: true,
gridview: true,
jsonReader: { repeatitems : false, root:"list" },
subGrid: true,
/*subGridModel: [{
//subgrid columns names
name: ['Name', 'Version', 'Information'],
//subgrid columns widths
width: [200, 100, 100],
//subrig columns aligns
align: ['left', 'left', 'left']
}]*/
// define the icons in subgrid
subGridOptions: {
"plusicon" : "ui-icon-triangle-1-e",
"minusicon" : "ui-icon-triangle-1-s",
"openicon" : "ui-icon-arrowreturn-1-e",
//expand all rows on load
"expandOnLoad" : true
},
subGridRowExpanded: function(subgrid_id, row_id) {
var subgrid_table_id, pager_id;
subgrid_table_id = subgrid_id+"_t";
pager_id = "p_"+subgrid_table_id;
$("#"+subgrid_id).html("<table id='"+subgrid_table_id+"' class='scroll'></table><div id='"+pager_id+"' class='scroll'></div>");
jQuery("#"+subgrid_table_id).jqGrid({
datastr : myJSONObject,
datatype: 'jsonstring',
colNames: ['Name','Value1','Value2'],
colModel: [
{name:"name",index:"name",width:90},
{name:"firstValue",index:"firstValue",width:100},
{name:"secondValue",index:"secondValue",width:100},
],
rowNum:20,
pager: pager_id,
sortname: 'name',
sortorder: "asc",
height: 'auto',
autowidth:true,
jsonReader: { repeatitems : false, root:"attribute" }
});
jQuery("#"+subgrid_table_id).jqGrid('navGrid',"#"+pager_id,{edit:false,add:false,del:false})
}
});
grid.jqGrid('navGrid','#gridpager2',{add:false,edit:false,del:false});
Any type of suggestions/ments/solutions are wele. Thanks
My output
This is my 3rd question about JSON data for jqGrid's subgrid, till now I did not get a single ment. Please somebody help.
my 1st question
and the
2nd one
I am having trouble getting to know the json format to be used by a subgrid in jqGrid. In my 2nd question i asked about the format that I should be using for a particular scenario
for the given image
Is this the proper JSON String?
var myJSONObject = {
"list": [
{
"elementName": "TERM",
"attribute": [
{
"name": "information",
"firstValue": "Required fixes for AIX",
"secondValue": "Required fixes for AIX"
},
{
"name": "name",
"firstValue": "PHCO_34",
"secondValue": "PHCO_34"
},
{
"name": "version",
"firstValue": "1.0",
"secondValue": "2.0"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": false
},
{
"elementName": "Asian-Core.ASX-JPN-MAN",
"attribute": [
{
"name": "information",
"firstValue": "Man",
"secondValue": "Man"
},
{
"name": "name",
"firstValue": "Asian-Core.ASX-JPN-MAN",
"secondValue": "Asian-Core.ASX-JPN-MAN"
},
{
"name": "version",
"firstValue": "B.11.23",
"secondValue": "B.11.23"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": true
}
]
};
If yes, my 1st question this is where i reached so far
$('#pareContent').empty();
$('<div id="pareParentDiv" width="100%">')
.html('<table id="list2" cellspacing="0" cellpadding="0"></table>'+
'<div id="gridpager2"></div></div>')
.appendTo('#pareContent');
var grid = jQuery("#list2");
grid.jqGrid({
datastr : myJSONObject,
datatype: 'jsonstring',
colNames:['Name','Result1', 'Result2'],
colModel:[
{name:'elementName',index:'elementName', width:90},
{name:'isPrasentinXml1',index:'isPrasentinXml1', width:100},
{name:'isPrasentinXml2',index:'isPrasentinXml2', width:100},
],
pager : '#gridpager2',
rowNum:10,
scrollOffset:0,
height: 'auto',
autowidth:true,
viewrecords: true,
gridview: true,
jsonReader: { repeatitems : false, root:"list" },
subGrid: true,
/*subGridModel: [{
//subgrid columns names
name: ['Name', 'Version', 'Information'],
//subgrid columns widths
width: [200, 100, 100],
//subrig columns aligns
align: ['left', 'left', 'left']
}]*/
// define the icons in subgrid
subGridOptions: {
"plusicon" : "ui-icon-triangle-1-e",
"minusicon" : "ui-icon-triangle-1-s",
"openicon" : "ui-icon-arrowreturn-1-e",
//expand all rows on load
"expandOnLoad" : true
},
subGridRowExpanded: function(subgrid_id, row_id) {
var subgrid_table_id, pager_id;
subgrid_table_id = subgrid_id+"_t";
pager_id = "p_"+subgrid_table_id;
$("#"+subgrid_id).html("<table id='"+subgrid_table_id+"' class='scroll'></table><div id='"+pager_id+"' class='scroll'></div>");
jQuery("#"+subgrid_table_id).jqGrid({
datastr : myJSONObject,
datatype: 'jsonstring',
colNames: ['Name','Value1','Value2'],
colModel: [
{name:"name",index:"name",width:90},
{name:"firstValue",index:"firstValue",width:100},
{name:"secondValue",index:"secondValue",width:100},
],
rowNum:20,
pager: pager_id,
sortname: 'name',
sortorder: "asc",
height: 'auto',
autowidth:true,
jsonReader: { repeatitems : false, root:"attribute" }
});
jQuery("#"+subgrid_table_id).jqGrid('navGrid',"#"+pager_id,{edit:false,add:false,del:false})
}
});
grid.jqGrid('navGrid','#gridpager2',{add:false,edit:false,del:false});
Any type of suggestions/ments/solutions are wele. Thanks
My output
Share Improve this question edited May 23, 2017 at 10:29 CommunityBot 11 silver badge asked Jul 11, 2011 at 11:30 AabinGunzAabinGunz 12.4k54 gold badges148 silver badges220 bronze badges 8- 3 you can verify json at jsonlint. – Rafay Commented Jul 11, 2011 at 11:32
- @3nigma: Good resource, Also I needed to know for this particular subgrid is my json string good enought, because the subgrid does not get populated – AabinGunz Commented Jul 11, 2011 at 11:41
- @Oleg: Please take a look at my questions :) – AabinGunz Commented Jul 11, 2011 at 11:42
-
can you post a link to documentation i think the datatype should be
json
instead ofjsonstring
– Rafay Commented Jul 11, 2011 at 12:09 - 2 @Abhishek Simon: To send a message to me you should write a ment to a question/answer where I wrote something. If you just write "@Oleg" text in the ment to your new question I receive no notification about this. See here for details. – Oleg Commented Jul 11, 2011 at 12:48
2 Answers
Reset to default 3You code has small errors in the declaration of the myJSONObject
variable and the code which create the contain of the div#pareContent
should be fixed to
$('#pareContent').empty();
$('<div id="pareParentDiv" width="100%">'+
'<table id="list2" cellspacing="0" cellpadding="0"></table>'+
'<div id="gridpager2"></div></div>')
.appendTo('#pareContent');
Small other syntax errors are the trailing mas in the colModel
: the ma before ']' should be removed.
Now to your main problem. You should change datastr : myJSONObject
in the subgrid to something like
datastr : myJSONObject.list[0]
then the modified demo will show the data: see here.
One more problem which you has is the absent of ids in your data. You should modify the structure of the data to define the unique ids for very grid row and every subgrid row. You should take in the considerations that ids from the data will be used as id of <tr>
elements and HTML don't permit to have id duplicates on one HTML page.
UPDATED: See here an example of modification of your JSON input and the jqGrid so that ids will be used.
a couple of suggestion that may/maynot workout
when using subgrid select the grid as
var mygrid = jQuery("#mygrid")[0];
replace
var grid = jQuery("#list2");
with
var grid = jQuery("#list2")[0];
Ref: http://www.trirand./blog/?page_id=393/help/2-questions-about-jqgrid-subgrid-and-jsonstring
also change your json to a valid
json
{
"list": [
{
"elementName": "TERM",
"attribute": [
{
"name": "information",
"firstValue": "RequiredfixesforAIX",
"secondValue": "RequiredfixesforAIX"
},
{
"name": "name",
"firstValue": "PHCO_34",
"secondValue": "PHCO_34"
},
{
"name": "version",
"firstValue": "1.0",
"secondValue": "2.0"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": false
}
]
}
verfified by www.jsonlint.
you may find the following link useful
jqGrid with JSON data renders table as empty
本文标签: javascriptJSON Object for jqGrid subgridStack Overflow
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